Base | Representation |
---|---|
bin | 10011011000000011000… |
… | …100011010110101011111 |
3 | 11201021210220212212210221 |
4 | 103120003010122311133 |
5 | 133303343241230103 |
6 | 2455402332342211 |
7 | 165124411516066 |
oct | 23300304326537 |
9 | 4637726785727 |
10 | 1331491351903 |
11 | 473756179a59 |
12 | 196075914967 |
13 | 9873644438b |
14 | 48631ac51dd |
15 | 2497d93b1bd |
hex | 1360311ad5f |
1331491351903 has 2 divisors, whose sum is σ = 1331491351904. Its totient is φ = 1331491351902.
The previous prime is 1331491351901. The next prime is 1331491351937. The reversal of 1331491351903 is 3091531941331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1331491351903 - 21 = 1331491351901 is a prime.
Together with 1331491351901, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1331491351903.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1331491351901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665745675951 + 665745675952.
It is an arithmetic number, because the mean of its divisors is an integer number (665745675952).
Almost surely, 21331491351903 is an apocalyptic number.
1331491351903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331491351903 is an equidigital number, since it uses as much as digits as its factorization.
1331491351903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 131220, while the sum is 43.
The spelling of 1331491351903 in words is "one trillion, three hundred thirty-one billion, four hundred ninety-one million, three hundred fifty-one thousand, nine hundred three".
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