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133151143105200 = 243521111251896561
BaseRepresentation
bin11110010001100110101010…
…100101100001001010110000
3122110110010101002200211122010
4132101212222211201022300
5114423022020113331300
61151104442442442520
740021565311153203
oct3621465245411260
9573403332624563
10133151143105200
11394760a00489a0
1212b25700503440
13593b13942823c
1424c479a5a593a
15105d877e19a50
hex7919aa9612b0

133151143105200 has 240 divisors, whose sum is σ = 465344597503872. Its totient is φ = 32276160000000.

The previous prime is 133151143105159. The next prime is 133151143105247. The reversal of 133151143105200 is 2501341151331.

It is a tau number, because it is divible by the number of its divisors (240).

It is a super-3 number, since 3×1331511431052003 (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 148064920 + ... + 148961480.

Almost surely, 2133151143105200 is an apocalyptic number.

133151143105200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133151143105200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (232672298751936).

133151143105200 is an abundant number, since it is smaller than the sum of its proper divisors (332193454398672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133151143105200 is a wasteful number, since it uses less digits than its factorization.

133151143105200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 907844 (or 907833 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 133151143105200 its reverse (2501341151331), we get a palindrome (135652484256531).

The spelling of 133151143105200 in words is "one hundred thirty-three trillion, one hundred fifty-one billion, one hundred forty-three million, one hundred five thousand, two hundred".