Base | Representation |
---|---|
bin | 111110000001101110… |
… | …0010001010011100000 |
3 | 110201211001112220202121 |
4 | 1330003130101103200 |
5 | 4140244120304421 |
6 | 141105251154024 |
7 | 12423602004316 |
oct | 1740334212340 |
9 | 421731486677 |
10 | 133201728736 |
11 | 515439a333a |
12 | 21994ba5914 |
13 | c73a2ca18b |
14 | 66387c40b6 |
15 | 36e8ea3d41 |
hex | 1f037114e0 |
133201728736 has 48 divisors (see below), whose sum is σ = 277730316864. Its totient is φ = 62668836864.
The previous prime is 133201728733. The next prime is 133201728767. The reversal of 133201728736 is 637827102331.
It is a junction number, because it is equal to n+sod(n) for n = 133201728692 and 133201728701.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133201728731) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2576356 + ... + 2627548.
It is an arithmetic number, because the mean of its divisors is an integer number (5786048268).
Almost surely, 2133201728736 is an apocalyptic number.
133201728736 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
133201728736 is an abundant number, since it is smaller than the sum of its proper divisors (144528588128).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133201728736 is a wasteful number, since it uses less digits than its factorization.
133201728736 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56003 (or 55995 counting only the distinct ones).
The product of its (nonzero) digits is 254016, while the sum is 43.
The spelling of 133201728736 in words is "one hundred thirty-three billion, two hundred one million, seven hundred twenty-eight thousand, seven hundred thirty-six".
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