1332020020231 has 2 divisors, whose sum is σ = 1332020020232. Its totient is φ = 1332020020230.

The previous prime is 1332020020213. The next prime is 1332020020249. The reversal of 1332020020231 is 1320200202331.

Together with previous prime (1332020020213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1332020020213) and next prime (1332020020249).

It is a cyclic number.

It is not a de Polignac number, because 1332020020231 - 2¹¹ = 1332020018183 is a prime.

It is a super-2 number, since 2×1332020020231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1332020020199 and 1332020020208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332020020291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666010010115 + 666010010116.

It is an arithmetic number, because the mean of its divisors is an integer number (666010010116).

Almost surely, 2^{1332020020231} is an apocalyptic number.

1332020020231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332020020231 is an equidigital number, since it uses as much as digits as its factorization.

1332020020231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 1332020020231 its reverse (1320200202331), we get a palindrome (2652220222562).

The spelling of 1332020020231 in words is "one trillion, three hundred thirty-two billion, twenty million, twenty thousand, two hundred thirty-one".