1332020212511 has 2 divisors, whose sum is σ = 1332020212512. Its totient is φ = 1332020212510.

The previous prime is 1332020212451. The next prime is 1332020212513. The reversal of 1332020212511 is 1152120202331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1332020212511 - 2¹⁸ = 1332019950367 is a prime.

Together with 1332020212513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332020212513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666010106255 + 666010106256.

It is an arithmetic number, because the mean of its divisors is an integer number (666010106256).

Almost surely, 2^{1332020212511} is an apocalyptic number.

1332020212511 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332020212511 is an equidigital number, since it uses as much as digits as its factorization.

1332020212511 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 1332020212511 its reverse (1152120202331), we get a palindrome (2484140414842).

The spelling of 1332020212511 in words is "one trillion, three hundred thirty-two billion, twenty million, two hundred twelve thousand, five hundred eleven".