133202103410491 has 2 divisors, whose sum is σ = 133202103410492. Its totient is φ = 133202103410490.

The previous prime is 133202103410489. The next prime is 133202103410527. The reversal of 133202103410491 is 194014301202331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133202103410491 - 2¹ = 133202103410489 is a prime.

It is a super-2 number, since 2×133202103410491² (a number of 29 digits) contains 22 as substring.

Together with 133202103410489, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (133202103410291) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66601051705245 + 66601051705246.

It is an arithmetic number, because the mean of its divisors is an integer number (66601051705246).

Almost surely, 2^{133202103410491} is an apocalyptic number.

133202103410491 is a deficient number, since it is larger than the sum of its proper divisors (1).

133202103410491 is an equidigital number, since it uses as much as digits as its factorization.

133202103410491 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 34.

The spelling of 133202103410491 in words is "one hundred thirty-three trillion, two hundred two billion, one hundred three million, four hundred ten thousand, four hundred ninety-one".