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13320211123253 is a prime number
BaseRepresentation
bin1100000111010101101001…
…1100111100110000110101
31202011101210102012222221002
43001311122130330300311
53221214243021421003
644155115344133045
72543232151263446
oct301653234746065
952141712188832
1013320211123253
114276084a16041
1215b1667907185
13758123b41b48
143409b74c92cd
151817513b6a88
hexc1d5a73cc35

13320211123253 has 2 divisors, whose sum is σ = 13320211123254. Its totient is φ = 13320211123252.

The previous prime is 13320211123223. The next prime is 13320211123259. The reversal of 13320211123253 is 35232111202331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10270602029284 + 3049609093969 = 3204778^2 + 1746313^2 .

It is a cyclic number.

It is not a de Polignac number, because 13320211123253 - 212 = 13320211119157 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13320211123259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660105561626 + 6660105561627.

It is an arithmetic number, because the mean of its divisors is an integer number (6660105561627).

Almost surely, 213320211123253 is an apocalyptic number.

It is an amenable number.

13320211123253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320211123253 is an equidigital number, since it uses as much as digits as its factorization.

13320211123253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 13320211123253 its reverse (35232111202331), we get a palindrome (48552322325584).

The spelling of 13320211123253 in words is "thirteen trillion, three hundred twenty billion, two hundred eleven million, one hundred twenty-three thousand, two hundred fifty-three".