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133202120130 = 23251480023557
BaseRepresentation
bin111110000001101110…
…1110000110111000010
3110201211002021210122200
41330003131300313002
54140244220321010
6141105303414030
712423605224362
oct1740335606702
9421732253580
10133202120130
1151544140402
1221995154316
13c73a406381
1466388869a2
1536e902ecc0
hex1f03770dc2

133202120130 has 24 divisors (see below), whose sum is σ = 346325512572. Its totient is φ = 35520565344.

The previous prime is 133202120111. The next prime is 133202120131. The reversal of 133202120130 is 31021202331.

133202120130 is a `hidden beast` number, since 1 + 3 + 320 + 212 + 0 + 130 = 666.

133202120130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 133059341529 + 142778601 = 364773^2 + 11949^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (133202120131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 740011689 + ... + 740011868.

Almost surely, 2133202120130 is an apocalyptic number.

133202120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

133202120130 is an abundant number, since it is smaller than the sum of its proper divisors (213123392442).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133202120130 is a wasteful number, since it uses less digits than its factorization.

133202120130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1480023570 (or 1480023567 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 133202120130 its reverse (31021202331), we get a palindrome (164223322461).

The spelling of 133202120130 in words is "one hundred thirty-three billion, two hundred two million, one hundred twenty thousand, one hundred thirty".

Divisors: 1 2 3 5 6 9 10 15 18 30 45 90 1480023557 2960047114 4440070671 7400117785 8880141342 13320212013 14800235570 22200353355 26640424026 44400706710 66601060065 133202120130