Base | Representation |
---|---|
bin | 111110000001101110… |
… | …1110000110111000010 |
3 | 110201211002021210122200 |
4 | 1330003131300313002 |
5 | 4140244220321010 |
6 | 141105303414030 |
7 | 12423605224362 |
oct | 1740335606702 |
9 | 421732253580 |
10 | 133202120130 |
11 | 51544140402 |
12 | 21995154316 |
13 | c73a406381 |
14 | 66388869a2 |
15 | 36e902ecc0 |
hex | 1f03770dc2 |
133202120130 has 24 divisors (see below), whose sum is σ = 346325512572. Its totient is φ = 35520565344.
The previous prime is 133202120111. The next prime is 133202120131. The reversal of 133202120130 is 31021202331.
133202120130 is a `hidden beast` number, since 1 + 3 + 320 + 212 + 0 + 130 = 666.
133202120130 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 2 ways, for example, as 133059341529 + 142778601 = 364773^2 + 11949^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (133202120131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 740011689 + ... + 740011868.
Almost surely, 2133202120130 is an apocalyptic number.
133202120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133202120130 is an abundant number, since it is smaller than the sum of its proper divisors (213123392442).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133202120130 is a wasteful number, since it uses less digits than its factorization.
133202120130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1480023570 (or 1480023567 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 18.
Adding to 133202120130 its reverse (31021202331), we get a palindrome (164223322461).
The spelling of 133202120130 in words is "one hundred thirty-three billion, two hundred two million, one hundred twenty thousand, one hundred thirty".
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