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13320233203327 is a prime number
BaseRepresentation
bin1100000111010101101111…
…0001001011011001111111
31202011101211221202210002121
43001311123301023121333
53221214314200001302
644155121453303411
72543232540045031
oct301653361133177
952141757683077
1013320233203327
114276096427136
1215b1673194b67
137581285a2c8b
143409ba3d5c51
151817532c8e37
hexc1d5bc4b67f

13320233203327 has 2 divisors, whose sum is σ = 13320233203328. Its totient is φ = 13320233203326.

The previous prime is 13320233203313. The next prime is 13320233203337. The reversal of 13320233203327 is 72330233202331.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13320233203327 is a prime.

It is a super-2 number, since 2×133202332033272 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13320233203292 and 13320233203301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13320233203337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660116601663 + 6660116601664.

It is an arithmetic number, because the mean of its divisors is an integer number (6660116601664).

Almost surely, 213320233203327 is an apocalyptic number.

13320233203327 is a deficient number, since it is larger than the sum of its proper divisors (1).

13320233203327 is an equidigital number, since it uses as much as digits as its factorization.

13320233203327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81648, while the sum is 34.

Adding to 13320233203327 its reverse (72330233202331), we get a palindrome (85650466405658).

The spelling of 13320233203327 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-three million, two hundred three thousand, three hundred twenty-seven".