1332024442340 has 48 divisors (see below), whose sum is σ = 2803654560000. Its totient is φ = 531590729472.

The previous prime is 1332024442321. The next prime is 1332024442363. The reversal of 1332024442340 is 432444202331.

It is a super-2 number, since 2×1332024442340² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1332024442297 and 1332024442306.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39094592 + ... + 39128648.

It is an arithmetic number, because the mean of its divisors is an integer number (58409470000).

Almost surely, 2^{1332024442340} is an apocalyptic number.

1332024442340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1332024442340 is an abundant number, since it is smaller than the sum of its proper divisors (1471630117660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1332024442340 is a wasteful number, since it uses less digits than its factorization.

1332024442340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38484 (or 38482 counting only the distinct ones).

The product of its (nonzero) digits is 55296, while the sum is 32.

Adding to 1332024442340 its reverse (432444202331), we get a palindrome (1764468644671).

The spelling of 1332024442340 in words is "one trillion, three hundred thirty-two billion, twenty-four million, four hundred forty-two thousand, three hundred forty".