Base | Representation |
---|---|
bin | 1100000111010110000001… |
… | …1111010101001111011111 |
3 | 1202011102001110210221201221 |
4 | 3001311200133111033133 |
5 | 3221214444434123403 |
6 | 44155133403114211 |
7 | 2543234521231345 |
oct | 301654037251737 |
9 | 52142043727657 |
10 | 13320312411103 |
11 | 4276127107105 |
12 | 15b1695812967 |
13 | 75813bb16899 |
14 | 3409c6b33995 |
15 | 18175a222dbd |
hex | c1d607d53df |
13320312411103 has 2 divisors, whose sum is σ = 13320312411104. Its totient is φ = 13320312411102.
The previous prime is 13320312411097. The next prime is 13320312411121. The reversal of 13320312411103 is 30111421302331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13320312411103 - 217 = 13320312280031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13320312411193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660156205551 + 6660156205552.
It is an arithmetic number, because the mean of its divisors is an integer number (6660156205552).
Almost surely, 213320312411103 is an apocalyptic number.
13320312411103 is a deficient number, since it is larger than the sum of its proper divisors (1).
13320312411103 is an equidigital number, since it uses as much as digits as its factorization.
13320312411103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 13320312411103 its reverse (30111421302331), we get a palindrome (43431733713434).
The spelling of 13320312411103 in words is "thirteen trillion, three hundred twenty billion, three hundred twelve million, four hundred eleven thousand, one hundred three".
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