Base | Representation |
---|---|
bin | 111110000001110011… |
… | …0001000010110110111 |
3 | 110201211020102020102121 |
4 | 1330003212020112313 |
5 | 4140300301013102 |
6 | 141105422420411 |
7 | 12423632661205 |
oct | 1740346102667 |
9 | 421736366377 |
10 | 133204313527 |
11 | 515453a932a |
12 | 21995a31707 |
13 | c73a9c383c |
14 | 6638c98075 |
15 | 36e9314b37 |
hex | 1f039885b7 |
133204313527 has 2 divisors, whose sum is σ = 133204313528. Its totient is φ = 133204313526.
The previous prime is 133204313507. The next prime is 133204313549. The reversal of 133204313527 is 725313402331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133204313527 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133204313492 and 133204313501.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133204313507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66602156763 + 66602156764.
It is an arithmetic number, because the mean of its divisors is an integer number (66602156764).
Almost surely, 2133204313527 is an apocalyptic number.
133204313527 is a deficient number, since it is larger than the sum of its proper divisors (1).
133204313527 is an equidigital number, since it uses as much as digits as its factorization.
133204313527 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 45360, while the sum is 34.
Adding to 133204313527 its reverse (725313402331), we get a palindrome (858517715858).
The spelling of 133204313527 in words is "one hundred thirty-three billion, two hundred four million, three hundred thirteen thousand, five hundred twenty-seven".
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