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133204522142309 is a prime number
BaseRepresentation
bin11110010010011000011000…
…001110011000101001100101
3122110122020011011202212202112
4132102120120032120221211
5114424410330132023214
61151145151312450405
740025465143404122
oct3622303016305145
9573566134685675
10133204522142309
11394967a21295a2
1212b33b18b49a05
1359431952612b7
1424c71c19a7749
15105ee4e275a3e
hex792618398a65

133204522142309 has 2 divisors, whose sum is σ = 133204522142310. Its totient is φ = 133204522142308.

The previous prime is 133204522142249. The next prime is 133204522142347. The reversal of 133204522142309 is 903241225402331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73404026788225 + 59800495354084 = 8567615^2 + 7733078^2 .

It is an emirp because it is prime and its reverse (903241225402331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133204522142309 - 244 = 115612336097893 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133204522142369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66602261071154 + 66602261071155.

It is an arithmetic number, because the mean of its divisors is an integer number (66602261071155).

Almost surely, 2133204522142309 is an apocalyptic number.

It is an amenable number.

133204522142309 is a deficient number, since it is larger than the sum of its proper divisors (1).

133204522142309 is an equidigital number, since it uses as much as digits as its factorization.

133204522142309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 133204522142309 in words is "one hundred thirty-three trillion, two hundred four billion, five hundred twenty-two million, one hundred forty-two thousand, three hundred nine".