Base | Representation |
---|---|
bin | 11110010010011000011000… |
… | …001110011000101010001011 |
3 | 122110122020011011202212210221 |
4 | 132102120120032120222023 |
5 | 114424410330132023342 |
6 | 1151145151312450511 |
7 | 40025465143404205 |
oct | 3622303016305213 |
9 | 573566134685727 |
10 | 133204522142347 |
11 | 394967a2129627 |
12 | 12b33b18b49a37 |
13 | 5943195261316 |
14 | 24c71c19a7775 |
15 | 105ee4e275a67 |
hex | 792618398a8b |
133204522142347 has 2 divisors, whose sum is σ = 133204522142348. Its totient is φ = 133204522142346.
The previous prime is 133204522142309. The next prime is 133204522142369. The reversal of 133204522142347 is 743241225402331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133204522142347 - 211 = 133204522140299 is a prime.
It is not a weakly prime, because it can be changed into another prime (133204522142147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66602261071173 + 66602261071174.
It is an arithmetic number, because the mean of its divisors is an integer number (66602261071174).
Almost surely, 2133204522142347 is an apocalyptic number.
133204522142347 is a deficient number, since it is larger than the sum of its proper divisors (1).
133204522142347 is an equidigital number, since it uses as much as digits as its factorization.
133204522142347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 967680, while the sum is 43.
Adding to 133204522142347 its reverse (743241225402331), we get a palindrome (876445747544678).
The spelling of 133204522142347 in words is "one hundred thirty-three trillion, two hundred four billion, five hundred twenty-two million, one hundred forty-two thousand, three hundred forty-seven".
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