Base | Representation |
---|---|
bin | 1100000111011000101010… |
… | …1110110011111101101101 |
3 | 1202011110212212100200211201 |
4 | 3001312022232303331231 |
5 | 3221222422401042143 |
6 | 44155332001045501 |
7 | 2543261215132255 |
oct | 301661256637555 |
9 | 52143785320751 |
10 | 13321021112173 |
11 | 4276460159775 |
12 | 15b1853026891 |
13 | 7582228b1528 |
14 | 340a52cd4965 |
15 | 18179c56364d |
hex | c1d8abb3f6d |
13321021112173 has 2 divisors, whose sum is σ = 13321021112174. Its totient is φ = 13321021112172.
The previous prime is 13321021112093. The next prime is 13321021112207. The reversal of 13321021112173 is 37121112012331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6738291855684 + 6582729256489 = 2595822^2 + 2565683^2 .
It is a cyclic number.
It is not a de Polignac number, because 13321021112173 - 221 = 13321019015021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13321021112573) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660510556086 + 6660510556087.
It is an arithmetic number, because the mean of its divisors is an integer number (6660510556087).
Almost surely, 213321021112173 is an apocalyptic number.
It is an amenable number.
13321021112173 is a deficient number, since it is larger than the sum of its proper divisors (1).
13321021112173 is an equidigital number, since it uses as much as digits as its factorization.
13321021112173 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 28.
The spelling of 13321021112173 in words is "thirteen trillion, three hundred twenty-one billion, twenty-one million, one hundred twelve thousand, one hundred seventy-three".
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