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13321023300043 is a prime number
BaseRepresentation
bin1100000111011000101011…
…0111001010000111001011
31202011110220000110212000221
43001312022313022013023
53221222423431100133
644155332120010511
72543261242544014
oct301661267120713
952143800425027
1013321023300043
114276461413528
1215b1853900a37
13758223199324
14340a5330400b
1518179c846a2d
hexc1d8adca1cb

13321023300043 has 2 divisors, whose sum is σ = 13321023300044. Its totient is φ = 13321023300042.

The previous prime is 13321023300037. The next prime is 13321023300049. The reversal of 13321023300043 is 34000332012331.

13321023300043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13321023300037) and next prime (13321023300049).

It is a cyclic number.

It is not a de Polignac number, because 13321023300043 - 225 = 13320989745611 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13321023299990 and 13321023300017.

It is not a weakly prime, because it can be changed into another prime (13321023300049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660511650021 + 6660511650022.

It is an arithmetic number, because the mean of its divisors is an integer number (6660511650022).

Almost surely, 213321023300043 is an apocalyptic number.

13321023300043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321023300043 is an equidigital number, since it uses as much as digits as its factorization.

13321023300043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 13321023300043 its reverse (34000332012331), we get a palindrome (47321355312374).

The spelling of 13321023300043 in words is "thirteen trillion, three hundred twenty-one billion, twenty-three million, three hundred thousand, forty-three".