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13321105025477 is a prime number
BaseRepresentation
bin1100000111011000111110…
…1110111010100111000101
31202011111002201020221020212
43001312033232322213011
53221223110341303402
644155344155405205
72543263254314414
oct301661756724705
952144081227225
1013321105025477
1142764a3563007
1215b1877153805
137582370b1b82
14340a600d947b
151817a4adb952
hexc1d8fbba9c5

13321105025477 has 2 divisors, whose sum is σ = 13321105025478. Its totient is φ = 13321105025476.

The previous prime is 13321105025413. The next prime is 13321105025491. The reversal of 13321105025477 is 77452050112331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9158909324161 + 4162195701316 = 3026369^2 + 2040146^2 .

It is a cyclic number.

It is not a de Polignac number, because 13321105025477 - 26 = 13321105025413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13321105055477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660552512738 + 6660552512739.

It is an arithmetic number, because the mean of its divisors is an integer number (6660552512739).

Almost surely, 213321105025477 is an apocalyptic number.

It is an amenable number.

13321105025477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321105025477 is an equidigital number, since it uses as much as digits as its factorization.

13321105025477 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 176400, while the sum is 41.

The spelling of 13321105025477 in words is "thirteen trillion, three hundred twenty-one billion, one hundred five million, twenty-five thousand, four hundred seventy-seven".