Base | Representation |
---|---|
bin | 111110000010000000… |
… | …0000110010101111111 |
3 | 110201211201020002120002 |
4 | 1330010000012111333 |
5 | 4140304021333043 |
6 | 141110224344515 |
7 | 12424044563141 |
oct | 1740400062577 |
9 | 421751202502 |
10 | 133211121023 |
11 | 51549228962 |
12 | 2199817513b |
13 | c73c238246 |
14 | 6639b4ac91 |
15 | 36e9c0bbb8 |
hex | 1f0400657f |
133211121023 has 2 divisors, whose sum is σ = 133211121024. Its totient is φ = 133211121022.
The previous prime is 133211120993. The next prime is 133211121061. The reversal of 133211121023 is 320121112331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133211121023 - 214 = 133211104639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133211120986 and 133211121004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133211121223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66605560511 + 66605560512.
It is an arithmetic number, because the mean of its divisors is an integer number (66605560512).
Almost surely, 2133211121023 is an apocalyptic number.
133211121023 is a deficient number, since it is larger than the sum of its proper divisors (1).
133211121023 is an equidigital number, since it uses as much as digits as its factorization.
133211121023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 133211121023 its reverse (320121112331), we get a palindrome (453332233354).
The spelling of 133211121023 in words is "one hundred thirty-three billion, two hundred eleven million, one hundred twenty-one thousand, twenty-three".
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