1332111312149 has 2 divisors, whose sum is σ = 1332111312150. Its totient is φ = 1332111312148.

The previous prime is 1332111312139. The next prime is 1332111312209. The reversal of 1332111312149 is 9412131112331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1036207951249 + 295903360900 = 1017943^2 + 543970^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1332111312149 is a prime.

It is a super-3 number, since 3×1332111312149³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332111312139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666055656074 + 666055656075.

It is an arithmetic number, because the mean of its divisors is an integer number (666055656075).

Almost surely, 2^{1332111312149} is an apocalyptic number.

It is an amenable number.

1332111312149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332111312149 is an equidigital number, since it uses as much as digits as its factorization.

1332111312149 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 32.

The spelling of 1332111312149 in words is "one trillion, three hundred thirty-two billion, one hundred eleven million, three hundred twelve thousand, one hundred forty-nine".