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13321212202157 is a prime number
BaseRepresentation
bin1100000111011001011000…
…0111110000110010101101
31202011111101011221002000112
43001312112013300302231
53221223320310432112
644155402544505405
72543266025310026
oct301662607606255
952144334832015
1013321212202157
114276549006482
1215b18a701b265
13758253369122
14340a70437c4d
151817ae20ca22
hexc1d961f0cad

13321212202157 has 2 divisors, whose sum is σ = 13321212202158. Its totient is φ = 13321212202156.

The previous prime is 13321212202153. The next prime is 13321212202169. The reversal of 13321212202157 is 75120221212331.

13321212202157 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13214635417636 + 106576784521 = 3635194^2 + 326461^2 .

It is a cyclic number.

It is not a de Polignac number, because 13321212202157 - 22 = 13321212202153 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13321212202153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6660606101078 + 6660606101079.

It is an arithmetic number, because the mean of its divisors is an integer number (6660606101079).

Almost surely, 213321212202157 is an apocalyptic number.

It is an amenable number.

13321212202157 is a deficient number, since it is larger than the sum of its proper divisors (1).

13321212202157 is an equidigital number, since it uses as much as digits as its factorization.

13321212202157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 32.

Adding to 13321212202157 its reverse (75120221212331), we get a palindrome (88441433414488).

The spelling of 13321212202157 in words is "thirteen trillion, three hundred twenty-one billion, two hundred twelve million, two hundred two thousand, one hundred fifty-seven".