Base | Representation |
---|---|
bin | 11110010010100110111010… |
… | …100011001111101000010111 |
3 | 122110200201102221111121022112 |
4 | 132102212322203033220113 |
5 | 114430134311341440041 |
6 | 1151200252200221235 |
7 | 40026560010523445 |
oct | 3622467243175027 |
9 | 573621387447275 |
10 | 133220130421271 |
11 | 394a23816435a3 |
12 | 12b36b5416a81b |
13 | 59447b1b1431a |
14 | 24c7c628cbb95 |
15 | 1060564690deb |
hex | 7929ba8cfa17 |
133220130421271 has 2 divisors, whose sum is σ = 133220130421272. Its totient is φ = 133220130421270.
The previous prime is 133220130421187. The next prime is 133220130421403. The reversal of 133220130421271 is 172124031022331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133220130421271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133220130421471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66610065210635 + 66610065210636.
It is an arithmetic number, because the mean of its divisors is an integer number (66610065210636).
Almost surely, 2133220130421271 is an apocalyptic number.
133220130421271 is a deficient number, since it is larger than the sum of its proper divisors (1).
133220130421271 is an equidigital number, since it uses as much as digits as its factorization.
133220130421271 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 133220130421271 in words is "one hundred thirty-three trillion, two hundred twenty billion, one hundred thirty million, four hundred twenty-one thousand, two hundred seventy-one".
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