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13322020304020 = 2251027616482041
BaseRepresentation
bin1100000111011100011001…
…0010011011010010010100
31202011120110111111220101011
43001313012102123102110
53221231444144212040
644200015053142004
72543325040126111
oct301670622332224
952146414456334
1013322020304020
11427692318035a
1215b1a9178a904
137583518c78cc
14340b098b1908
1518180a1353ea
hexc1dc649b494

13322020304020 has 24 divisors (see below), whose sum is σ = 27976519200168. Its totient is φ = 5328755443200.

The previous prime is 13322020303979. The next prime is 13322020304023. The reversal of 13322020304020 is 2040302022331.

It can be written as a sum of positive squares in 4 ways, for example, as 8066133928836 + 5255886375184 = 2840094^2 + 2292572^2 .

It is a super-2 number, since 2×133220203040202 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13322020303982 and 13322020304000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13322020304023) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1185801 + ... + 5296240.

It is an arithmetic number, because the mean of its divisors is an integer number (1165688300007).

Almost surely, 213322020304020 is an apocalyptic number.

13322020304020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13322020304020 is an abundant number, since it is smaller than the sum of its proper divisors (14654498896148).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13322020304020 is a wasteful number, since it uses less digits than its factorization.

13322020304020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6584811 (or 6584809 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 22.

Adding to 13322020304020 its reverse (2040302022331), we get a palindrome (15362322326351).

The spelling of 13322020304020 in words is "thirteen trillion, three hundred twenty-two billion, twenty million, three hundred four thousand, twenty".

Divisors: 1 2 4 5 10 20 102761 205522 411044 513805 1027610 2055220 6482041 12964082 25928164 32410205 64820410 129640820 666101015201 1332202030402 2664404060804 3330505076005 6661010152010 13322020304020