13322032021031 has 2 divisors, whose sum is σ = 13322032021032. Its totient is φ = 13322032021030.

The previous prime is 13322032020991. The next prime is 13322032021033. The reversal of 13322032021031 is 13012023022331.

It is a strong prime.

It is an emirp because it is prime and its reverse (13012023022331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13322032021031 is a prime.

It is a super-3 number, since 3×13322032021031³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 13322032021033, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13322032020988 and 13322032021006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13322032021033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661016010515 + 6661016010516.

It is an arithmetic number, because the mean of its divisors is an integer number (6661016010516).

Almost surely, 2^{13322032021031} is an apocalyptic number.

13322032021031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13322032021031 is an equidigital number, since it uses as much as digits as its factorization.

13322032021031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13322032021031 its reverse (13012023022331), we get a palindrome (26334055043362).

The spelling of 13322032021031 in words is "thirteen trillion, three hundred twenty-two billion, thirty-two million, twenty-one thousand, thirty-one".