Base | Representation |
---|---|
bin | 1100000111011100011100… |
… | …0010111110110101011111 |
3 | 1202011120111101110120121221 |
4 | 3001313013002332311133 |
5 | 3221232010424020133 |
6 | 44200020230034211 |
7 | 2543325253251364 |
oct | 301670702766537 |
9 | 52146441416557 |
10 | 13322033032543 |
11 | 427692a3844a4 |
12 | 15b1a95aa8967 |
13 | 758354433391 |
14 | 340b0b46646b |
15 | 18180b2eba2d |
hex | c1dc70bed5f |
13322033032543 has 2 divisors, whose sum is σ = 13322033032544. Its totient is φ = 13322033032542.
The previous prime is 13322033032459. The next prime is 13322033032547. The reversal of 13322033032543 is 34523033022331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13322033032543 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13322033032499 and 13322033032508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13322033032547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6661016516271 + 6661016516272.
It is an arithmetic number, because the mean of its divisors is an integer number (6661016516272).
Almost surely, 213322033032543 is an apocalyptic number.
13322033032543 is a deficient number, since it is larger than the sum of its proper divisors (1).
13322033032543 is an equidigital number, since it uses as much as digits as its factorization.
13322033032543 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 34.
Adding to 13322033032543 its reverse (34523033022331), we get a palindrome (47845066054874).
The spelling of 13322033032543 in words is "thirteen trillion, three hundred twenty-two billion, thirty-three million, thirty-two thousand, five hundred forty-three".
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