1332241319 has 2 divisors, whose sum is σ = 1332241320. Its totient is φ = 1332241318.

The previous prime is 1332241307. The next prime is 1332241321. The reversal of 1332241319 is 9131422331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1332241319 - 2²⁰ = 1331192743 is a prime.

It is a super-2 number, since 2×1332241319² = 3549733864101719522, which contains 22 as substring.

Together with 1332241321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1332241291 and 1332241300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1332241219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666120659 + 666120660.

It is an arithmetic number, because the mean of its divisors is an integer number (666120660).

Almost surely, 2^1332241319 is an apocalyptic number.

1332241319 is a deficient number, since it is larger than the sum of its proper divisors (1).

1332241319 is an equidigital number, since it uses as much as digits as its factorization.

1332241319 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3888, while the sum is 29.

The square root of 1332241319 is about 36499.8810819981. The cubic root of 1332241319 is about 1100.3418549053.

The spelling of 1332241319 in words is "one billion, three hundred thirty-two million, two hundred forty-one thousand, three hundred nineteen".