Base | Representation |
---|---|
bin | 11110010010110001000010… |
… | …101011000111010000101110 |
3 | 122110201202111202021201221011 |
4 | 132102301002223013100232 |
5 | 114430324044023320420 |
6 | 1151205251153255434 |
7 | 40030423324452361 |
oct | 3622610253072056 |
9 | 573652452251834 |
10 | 133231004120110 |
11 | 394a6a51556466 |
12 | 12b3908986457a |
13 | 5945825819950 |
14 | 24c85b4ac20d8 |
15 | 106099e0d295a |
hex | 792c42ac742e |
133231004120110 has 32 divisors (see below), whose sum is σ = 260770586731200. Its totient is φ = 48715384324608.
The previous prime is 133231004120041. The next prime is 133231004120119. The reversal of 133231004120110 is 11021400132331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133231004120119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4975005435 + ... + 4975032214.
It is an arithmetic number, because the mean of its divisors is an integer number (8149080835350).
Almost surely, 2133231004120110 is an apocalyptic number.
133231004120110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133231004120110 is a deficient number, since it is larger than the sum of its proper divisors (127539582611090).
133231004120110 is a wasteful number, since it uses less digits than its factorization.
133231004120110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9950037772.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 133231004120110 its reverse (11021400132331), we get a palindrome (144252404252441).
The spelling of 133231004120110 in words is "one hundred thirty-three trillion, two hundred thirty-one billion, four million, one hundred twenty thousand, one hundred ten".
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