Base | Representation |
---|---|
bin | 11110010010110001000011… |
… | …001001010000101110101011 |
3 | 122110201202112022011020221121 |
4 | 132102301003021100232223 |
5 | 114430324103034220321 |
6 | 1151205252034520111 |
7 | 40030423451566444 |
oct | 3622610311205653 |
9 | 573652468136847 |
10 | 133231012023211 |
11 | 394a6a55a64153 |
12 | 12b39090436037 |
13 | 5945827355c3b |
14 | 24c85b5b7c2cb |
15 | 106099eb44441 |
hex | 792c43250bab |
133231012023211 has 2 divisors, whose sum is σ = 133231012023212. Its totient is φ = 133231012023210.
The previous prime is 133231012023209. The next prime is 133231012023247. The reversal of 133231012023211 is 112320210132331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133231012023211 - 21 = 133231012023209 is a prime.
Together with 133231012023209, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (133231012023511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66615506011605 + 66615506011606.
It is an arithmetic number, because the mean of its divisors is an integer number (66615506011606).
Almost surely, 2133231012023211 is an apocalyptic number.
133231012023211 is a deficient number, since it is larger than the sum of its proper divisors (1).
133231012023211 is an equidigital number, since it uses as much as digits as its factorization.
133231012023211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 133231012023211 its reverse (112320210132331), we get a palindrome (245551222155542).
The spelling of 133231012023211 in words is "one hundred thirty-three trillion, two hundred thirty-one billion, twelve million, twenty-three thousand, two hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •