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13323241121140 = 2253346919903853
BaseRepresentation
bin1100000111100000111100…
…0011011110010101110100
31202011200121120200211122001
43001320033003132111310
53221241444211334030
644200340143345044
72543400222655516
oct301701703362564
952150546624561
1013323241121140
11427739a305325
1215b21725b2184
137584b77ca3c2
14340bc3a9dbb6
1518187c3d3cca
hexc1e0f0de574

13323241121140 has 24 divisors (see below), whose sum is σ = 27979643721960. Its totient is φ = 5329136949888.

The previous prime is 13323241121117. The next prime is 13323241121147. The reversal of 13323241121140 is 4112114232331.

13323241121140 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 302084342884 + 13021156778256 = 549622^2 + 3608484^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13323241121099 and 13323241121108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13323241121147) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9282547 + ... + 10621306.

It is an arithmetic number, because the mean of its divisors is an integer number (1165818488415).

Almost surely, 213323241121140 is an apocalyptic number.

13323241121140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13323241121140 is an abundant number, since it is smaller than the sum of its proper divisors (14656402600820).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13323241121140 is a wasteful number, since it uses less digits than its factorization.

13323241121140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19937331 (or 19937329 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 13323241121140 its reverse (4112114232331), we get a palindrome (17435355353471).

The spelling of 13323241121140 in words is "thirteen trillion, three hundred twenty-three billion, two hundred forty-one million, one hundred twenty-one thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 33469 66938 133876 167345 334690 669380 19903853 39807706 79615412 99519265 199038530 398077060 666162056057 1332324112114 2664648224228 3330810280285 6661620560570 13323241121140