Base | Representation |
---|---|
bin | 111110000010101110… |
… | …0011101011110111011 |
3 | 110201220101210012012212 |
4 | 1330011130131132323 |
5 | 4140331221124201 |
6 | 141112451325335 |
7 | 12424460434142 |
oct | 1740534353673 |
9 | 421811705185 |
10 | 133235333051 |
11 | 515609657a7 |
12 | 219a42b084b |
13 | c7442648a2 |
14 | 663d050759 |
15 | 36ebde0abb |
hex | 1f0571d7bb |
133235333051 has 2 divisors, whose sum is σ = 133235333052. Its totient is φ = 133235333050.
The previous prime is 133235333017. The next prime is 133235333053. The reversal of 133235333051 is 150333532331.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133235333051 is a prime.
It is a Sophie Germain prime.
Together with 133235333053, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 133235332999 and 133235333017.
It is not a weakly prime, because it can be changed into another prime (133235333053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66617666525 + 66617666526.
It is an arithmetic number, because the mean of its divisors is an integer number (66617666526).
Almost surely, 2133235333051 is an apocalyptic number.
133235333051 is a deficient number, since it is larger than the sum of its proper divisors (1).
133235333051 is an equidigital number, since it uses as much as digits as its factorization.
133235333051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36450, while the sum is 32.
Adding to 133235333051 its reverse (150333532331), we get a palindrome (283568865382).
The spelling of 133235333051 in words is "one hundred thirty-three billion, two hundred thirty-five million, three hundred thirty-three thousand, fifty-one".
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