Base | Representation |
---|---|
bin | 11000110100010110… |
… | …00001101100000111 |
3 | 1021101120110022220202 |
4 | 30122023001230013 |
5 | 204241421000012 |
6 | 10042043321115 |
7 | 651116063033 |
oct | 143213015407 |
9 | 37346408822 |
10 | 13324000007 |
11 | 571806145a |
12 | 26ba22019b |
13 | 1344553796 |
14 | 9057c91c3 |
15 | 52eb01cc2 |
hex | 31a2c1b07 |
13324000007 has 2 divisors, whose sum is σ = 13324000008. Its totient is φ = 13324000006.
The previous prime is 13323999961. The next prime is 13324000009. The reversal of 13324000007 is 70000042331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13324000007 - 212 = 13323995911 is a prime.
Together with 13324000009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13324000009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662000003 + 6662000004.
It is an arithmetic number, because the mean of its divisors is an integer number (6662000004).
Almost surely, 213324000007 is an apocalyptic number.
13324000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
13324000007 is an equidigital number, since it uses as much as digits as its factorization.
13324000007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 504, while the sum is 20.
Adding to 13324000007 its reverse (70000042331), we get a palindrome (83324042338).
The spelling of 13324000007 in words is "thirteen billion, three hundred twenty-four million, seven", and thus it is an aban number.
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