Base | Representation |
---|---|
bin | 11000110100100001… |
… | …11100000110110001 |
3 | 1021101200101002002221 |
4 | 30122100330012301 |
5 | 204242320100001 |
6 | 10042140441041 |
7 | 651135210001 |
oct | 143220740661 |
9 | 37350332087 |
10 | 13325550001 |
11 | 5718a1aa45 |
12 | 26ba849181 |
13 | 134497713a |
14 | 905ab0001 |
15 | 52ed0b1a1 |
hex | 31a43c1b1 |
13325550001 has 2 divisors, whose sum is σ = 13325550002. Its totient is φ = 13325550000.
The previous prime is 13325549999. The next prime is 13325550023. The reversal of 13325550001 is 10005552331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11438516401 + 1887033600 = 106951^2 + 43440^2 .
It is a cyclic number.
It is not a de Polignac number, because 13325550001 - 21 = 13325549999 is a prime.
It is a super-2 number, since 2×133255500012 (a number of 21 digits) contains 22 as substring.
Together with 13325549999, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13325550061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6662775000 + 6662775001.
It is an arithmetic number, because the mean of its divisors is an integer number (6662775001).
Almost surely, 213325550001 is an apocalyptic number.
It is an amenable number.
13325550001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13325550001 is an equidigital number, since it uses as much as digits as its factorization.
13325550001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2250, while the sum is 25.
The spelling of 13325550001 in words is "thirteen billion, three hundred twenty-five million, five hundred fifty thousand, one".
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