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133296047 is a prime number
BaseRepresentation
bin1111111000111…
…10111110101111
3100021211010210122
413330132332233
5233110433142
621120555155
73205666133
oct774367657
9307733718
10133296047
1169273325
1238782abb
1321800b01
14139bb3c3
15ba801d2
hex7f1efaf

133296047 has 2 divisors, whose sum is σ = 133296048. Its totient is φ = 133296046.

The previous prime is 133296011. The next prime is 133296049. The reversal of 133296047 is 740692331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133296047 - 216 = 133230511 is a prime.

It is a super-2 number, since 2×1332960472 = 35535672291652418, which contains 22 as substring.

Together with 133296049, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p7554365 and since 133296047 and 7554365 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 133295998 and 133296016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133296049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66648023 + 66648024.

It is an arithmetic number, because the mean of its divisors is an integer number (66648024).

Almost surely, 2133296047 is an apocalyptic number.

133296047 is a deficient number, since it is larger than the sum of its proper divisors (1).

133296047 is an equidigital number, since it uses as much as digits as its factorization.

133296047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 35.

The square root of 133296047 is about 11545.3907253068. The cubic root of 133296047 is about 510.8253290411.

It can be divided in two parts, 1332 and 96047, that added together give a palindrome (97379).

The spelling of 133296047 in words is "one hundred thirty-three million, two hundred ninety-six thousand, forty-seven".