Base | Representation |
---|---|
bin | 11110010011110101011010… |
… | …110111010001000110000011 |
3 | 122110222210000112111120100002 |
4 | 132103311122313101012003 |
5 | 114433024430121401311 |
6 | 1151303112424550215 |
7 | 40035632622535256 |
oct | 3623653267210603 |
9 | 573883015446302 |
10 | 133304424403331 |
11 | 395250a8377985 |
12 | 12b4b35a02236b |
13 | 594c72673c40c |
14 | 24cbd7ba6509d |
15 | 1062849b0593b |
hex | 793d5add1183 |
133304424403331 has 2 divisors, whose sum is σ = 133304424403332. Its totient is φ = 133304424403330.
The previous prime is 133304424403273. The next prime is 133304424403333.
133304424403331 is nontrivially palindromic in base 10.
It is a strong prime.
It is a palprime.
It is a cyclic number.
It is not a de Polignac number, because 133304424403331 - 246 = 62935680225667 is a prime.
It is a super-2 number, since 2×1333044244033312 (a number of 29 digits) contains 22 as substring.
Together with 133304424403333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (133304424403333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66652212201665 + 66652212201666.
It is an arithmetic number, because the mean of its divisors is an integer number (66652212201666).
Almost surely, 2133304424403331 is an apocalyptic number.
133304424403331 is a deficient number, since it is larger than the sum of its proper divisors (1).
133304424403331 is an equidigital number, since it uses as much as digits as its factorization.
133304424403331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 373248, while the sum is 38.
The spelling of 133304424403331 in words is "one hundred thirty-three trillion, three hundred four billion, four hundred twenty-four million, four hundred three thousand, three hundred thirty-one".
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