Search a number
-
+
133304424403331 is a prime number
BaseRepresentation
bin11110010011110101011010…
…110111010001000110000011
3122110222210000112111120100002
4132103311122313101012003
5114433024430121401311
61151303112424550215
740035632622535256
oct3623653267210603
9573883015446302
10133304424403331
11395250a8377985
1212b4b35a02236b
13594c72673c40c
1424cbd7ba6509d
151062849b0593b
hex793d5add1183

133304424403331 has 2 divisors, whose sum is σ = 133304424403332. Its totient is φ = 133304424403330.

The previous prime is 133304424403273. The next prime is 133304424403333.

133304424403331 is nontrivially palindromic in base 10.

It is a strong prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 133304424403331 - 246 = 62935680225667 is a prime.

It is a super-2 number, since 2×1333044244033312 (a number of 29 digits) contains 22 as substring.

Together with 133304424403333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (133304424403333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66652212201665 + 66652212201666.

It is an arithmetic number, because the mean of its divisors is an integer number (66652212201666).

Almost surely, 2133304424403331 is an apocalyptic number.

133304424403331 is a deficient number, since it is larger than the sum of its proper divisors (1).

133304424403331 is an equidigital number, since it uses as much as digits as its factorization.

133304424403331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 373248, while the sum is 38.

The spelling of 133304424403331 in words is "one hundred thirty-three trillion, three hundred four billion, four hundred twenty-four million, four hundred three thousand, three hundred thirty-one".