Base | Representation |
---|---|
bin | 1100000111111100100000… |
… | …0101000111110100111111 |
3 | 1202012101201020120100101011 |
4 | 3001333020011013310333 |
5 | 3221402122404233341 |
6 | 44204002301500051 |
7 | 2544051460001506 |
oct | 301771005076477 |
9 | 52171636510334 |
10 | 13330640305471 |
11 | 427a546a17aa5 |
12 | 15b3698571627 |
13 | 7590c671a598 |
14 | 3412c664b83d |
15 | 181b61c9eb81 |
hex | c1fc8147d3f |
13330640305471 has 2 divisors, whose sum is σ = 13330640305472. Its totient is φ = 13330640305470.
The previous prime is 13330640305427. The next prime is 13330640305537. The reversal of 13330640305471 is 17450304603331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13330640305471 - 211 = 13330640303423 is a prime.
It is a super-3 number, since 3×133306403054713 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13330640305771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665320152735 + 6665320152736.
It is an arithmetic number, because the mean of its divisors is an integer number (6665320152736).
Almost surely, 213330640305471 is an apocalyptic number.
13330640305471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13330640305471 is an equidigital number, since it uses as much as digits as its factorization.
13330640305471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 272160, while the sum is 40.
The spelling of 13330640305471 in words is "thirteen trillion, three hundred thirty billion, six hundred forty million, three hundred five thousand, four hundred seventy-one".
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