Base | Representation |
---|---|
bin | 1100000111111100100000… |
… | …0101000111110101000000 |
3 | 1202012101201020120100101012 |
4 | 3001333020011013311000 |
5 | 3221402122404233342 |
6 | 44204002301500052 |
7 | 2544051460001510 |
oct | 301771005076500 |
9 | 52171636510335 |
10 | 13330640305472 |
11 | 427a546a17aa6 |
12 | 15b3698571628 |
13 | 7590c671a599 |
14 | 3412c664b840 |
15 | 181b61c9eb82 |
hex | c1fc8147d40 |
13330640305472 has 28 divisors (see below), whose sum is σ = 30231987836640. Its totient is φ = 5713131559296.
The previous prime is 13330640305471. The next prime is 13330640305537. The reversal of 13330640305472 is 27450304603331.
It is a tau number, because it is divible by the number of its divisors (28).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13330640305471) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14877946322 + ... + 14877947217.
Almost surely, 213330640305472 is an apocalyptic number.
It is an amenable number.
13330640305472 is an abundant number, since it is smaller than the sum of its proper divisors (16901347531168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13330640305472 is an equidigital number, since it uses as much as digits as its factorization.
13330640305472 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29755893558 (or 29755893548 counting only the distinct ones).
The product of its (nonzero) digits is 544320, while the sum is 41.
The spelling of 13330640305472 in words is "thirteen trillion, three hundred thirty billion, six hundred forty million, three hundred five thousand, four hundred seventy-two".
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