Base | Representation |
---|---|
bin | 1100000111111101111101… |
… | …1000010100100010010000 |
3 | 1202012102201111010120101010 |
4 | 3001333133120110202100 |
5 | 3221403422442323344 |
6 | 44204105144210520 |
7 | 2544064244450253 |
oct | 301773730244220 |
9 | 52172644116333 |
10 | 13331031214224 |
11 | 427a727643589 |
12 | 15b3787469a40 |
13 | 7591596c7b39 |
14 | 34132252709a |
15 | 181b862698b9 |
hex | c1fdf614890 |
13331031214224 has 80 divisors (see below), whose sum is σ = 34479223938432. Its totient is φ = 4438425176064.
The previous prime is 13331031214211. The next prime is 13331031214231. The reversal of 13331031214224 is 42241213013331.
It is a super-2 number, since 2×133310312142242 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13331031214191 and 13331031214200.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 140053432 + ... + 140148584.
Almost surely, 213331031214224 is an apocalyptic number.
It is an amenable number.
13331031214224 is an abundant number, since it is smaller than the sum of its proper divisors (21148192724208).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13331031214224 is a wasteful number, since it uses less digits than its factorization.
13331031214224 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 98584 (or 98578 counting only the distinct ones).
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 13331031214224 its reverse (42241213013331), we get a palindrome (55572244227555).
The spelling of 13331031214224 in words is "thirteen trillion, three hundred thirty-one billion, thirty-one million, two hundred fourteen thousand, two hundred twenty-four".
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