133311114234340 has 48 divisors (see below), whose sum is σ = 322093967328000. Its totient is φ = 45399911571072.

The previous prime is 133311114234329. The next prime is 133311114234341. The reversal of 133311114234340 is 43432411113331.

It is a junction number, because it is equal to n+sod(n) for n = 133311114234296 and 133311114234305.

It is not an unprimeable number, because it can be changed into a prime (133311114234341) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3195355800 + ... + 3195397519.

It is an arithmetic number, because the mean of its divisors is an integer number (6710290986000).

Almost surely, 2^{133311114234340} is an apocalyptic number.

133311114234340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

133311114234340 is an abundant number, since it is smaller than the sum of its proper divisors (188782853093660).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133311114234340 is a wasteful number, since it uses less digits than its factorization.

133311114234340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6390753484 (or 6390753482 counting only the distinct ones).

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 133311114234340 its reverse (43432411113331), we get a palindrome (176743525347671).

The spelling of 133311114234340 in words is "one hundred thirty-three trillion, three hundred eleven billion, one hundred fourteen million, two hundred thirty-four thousand, three hundred forty".