Base | Representation |
---|---|
bin | 1100000111111110010010… |
… | …1110111001110001010111 |
3 | 1202012102221202010011201122 |
4 | 3001333210232321301113 |
5 | 3221404113440114431 |
6 | 44204122113114155 |
7 | 2544066415003535 |
oct | 301774456716127 |
9 | 52172852104648 |
10 | 13331121019991 |
11 | 427a773301a25 |
12 | 15b37b155895b |
13 | 7591721ac548 |
14 | 341330423155 |
15 | 181b8e0a8a7b |
hex | c1fe4bb9c57 |
13331121019991 has 2 divisors, whose sum is σ = 13331121019992. Its totient is φ = 13331121019990.
The previous prime is 13331121019903. The next prime is 13331121020057. The reversal of 13331121019991 is 19991012113331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13331121019991 - 222 = 13331116825687 is a prime.
It is a super-3 number, since 3×133311210199913 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13331121019291) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665560509995 + 6665560509996.
It is an arithmetic number, because the mean of its divisors is an integer number (6665560509996).
Almost surely, 213331121019991 is an apocalyptic number.
13331121019991 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331121019991 is an equidigital number, since it uses as much as digits as its factorization.
13331121019991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 39366, while the sum is 44.
The spelling of 13331121019991 in words is "thirteen trillion, three hundred thirty-one billion, one hundred twenty-one million, nineteen thousand, nine hundred ninety-one".
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