Base | Representation |
---|---|
bin | 10011011001100011101… |
… | …111011001100001000111 |
3 | 11201102222221201220021002 |
4 | 103121203233121201013 |
5 | 133320203441401211 |
6 | 2500231311043515 |
7 | 165212534333612 |
oct | 23314357314107 |
9 | 4642887656232 |
10 | 1333113231431 |
11 | 474408735063 |
12 | 196448b1059b |
13 | 9893446abc7 |
14 | 48747273179 |
15 | 24a2600d03b |
hex | 13663bd9847 |
1333113231431 has 2 divisors, whose sum is σ = 1333113231432. Its totient is φ = 1333113231430.
The previous prime is 1333113231419. The next prime is 1333113231473. The reversal of 1333113231431 is 1341323113331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1333113231431 - 214 = 1333113215047 is a prime.
It is a super-2 number, since 2×13331132314312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1333113231394 and 1333113231403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1333113237431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666556615715 + 666556615716.
It is an arithmetic number, because the mean of its divisors is an integer number (666556615716).
Almost surely, 21333113231431 is an apocalyptic number.
1333113231431 is a deficient number, since it is larger than the sum of its proper divisors (1).
1333113231431 is an equidigital number, since it uses as much as digits as its factorization.
1333113231431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5832, while the sum is 29.
Adding to 1333113231431 its reverse (1341323113331), we get a palindrome (2674436344762).
The spelling of 1333113231431 in words is "one trillion, three hundred thirty-three billion, one hundred thirteen million, two hundred thirty-one thousand, four hundred thirty-one".
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