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1333122001229 is a prime number
BaseRepresentation
bin10011011001100100010…
…000110110100101001101
311201110000120020110011102
4103121210100312211031
5133320213213014404
62500232223032445
7165213002020544
oct23314420664515
94643016213142
101333122001229
11474412684a27
1219644ba3b725
139893621b835
14487484b715b
1524a26b9171e
hex1366443694d

1333122001229 has 2 divisors, whose sum is σ = 1333122001230. Its totient is φ = 1333122001228.

The previous prime is 1333122001187. The next prime is 1333122001231. The reversal of 1333122001229 is 9221002213331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 935326897129 + 397795104100 = 967123^2 + 630710^2 .

It is a cyclic number.

It is not a de Polignac number, because 1333122001229 - 236 = 1264402524493 is a prime.

It is a super-3 number, since 3×13331220012293 (a number of 37 digits) contains 333 as substring.

Together with 1333122001231, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1333122001429) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666561000614 + 666561000615.

It is an arithmetic number, because the mean of its divisors is an integer number (666561000615).

Almost surely, 21333122001229 is an apocalyptic number.

It is an amenable number.

1333122001229 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333122001229 is an equidigital number, since it uses as much as digits as its factorization.

1333122001229 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 1333122001229 in words is "one trillion, three hundred thirty-three billion, one hundred twenty-two million, one thousand, two hundred twenty-nine".