1333122102133 has 2 divisors, whose sum is σ = 1333122102134. Its totient is φ = 1333122102132.

The previous prime is 1333122102107. The next prime is 1333122102139. The reversal of 1333122102133 is 3312012213331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 931315712209 + 401806389924 = 965047^2 + 633882^2 .

It is a cyclic number.

It is not a de Polignac number, because 1333122102133 - 2⁵ = 1333122102101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1333122102098 and 1333122102107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1333122102139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 666561051066 + 666561051067.

It is an arithmetic number, because the mean of its divisors is an integer number (666561051067).

Almost surely, 2^{1333122102133} is an apocalyptic number.

It is an amenable number.

1333122102133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1333122102133 is an equidigital number, since it uses as much as digits as its factorization.

1333122102133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1333122102133 its reverse (3312012213331), we get a palindrome (4645134315464).

The spelling of 1333122102133 in words is "one trillion, three hundred thirty-three billion, one hundred twenty-two million, one hundred two thousand, one hundred thirty-three".