Base | Representation |
---|---|
bin | 111110000101000010… |
… | …0101111101110100000 |
3 | 110202002210221012112102 |
4 | 1330022010233232200 |
5 | 4141011112034100 |
6 | 141124304145532 |
7 | 12426422552324 |
oct | 1741204575640 |
9 | 422083835472 |
10 | 133313002400 |
11 | 515a0794946 |
12 | 21a063082a8 |
13 | c75738a196 |
14 | 66494ab984 |
15 | 3703b33cd5 |
hex | 1f0a12fba0 |
133313002400 has 72 divisors (see below), whose sum is σ = 325551874284. Its totient is φ = 53308569600.
The previous prime is 133313002399. The next prime is 133313002411. The reversal of 133313002400 is 4200313331.
It can be written as a sum of positive squares in 6 ways, for example, as 6670968976 + 126642033424 = 81676^2 + 355868^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2722130 + ... + 2770670.
Almost surely, 2133313002400 is an apocalyptic number.
133313002400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133313002400 is an abundant number, since it is smaller than the sum of its proper divisors (192238871884).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133313002400 is a wasteful number, since it uses less digits than its factorization.
133313002400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51994 (or 51981 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 133313002400 its reverse (4200313331), we get a palindrome (137513315731).
The spelling of 133313002400 in words is "one hundred thirty-three billion, three hundred thirteen million, two thousand, four hundred".
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