13331310041020 has 24 divisors (see below), whose sum is σ = 27996041278800. Its totient is φ = 5332468741632.

The previous prime is 13331310040987. The next prime is 13331310041099. The reversal of 13331310041020 is 2014001313331.

It is a junction number, because it is equal to n+sod(n) for n = 13331310040982 and 13331310041000.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1448565 + ... + 5362924.

It is an arithmetic number, because the mean of its divisors is an integer number (1166501719950).

Almost surely, 2^{13331310041020} is an apocalyptic number.

13331310041020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13331310041020 is an abundant number, since it is smaller than the sum of its proper divisors (14664731237780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13331310041020 is a wasteful number, since it uses less digits than its factorization.

13331310041020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6909357 (or 6909355 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13331310041020 its reverse (2014001313331), we get a palindrome (15345311354351).

The spelling of 13331310041020 in words is "thirteen trillion, three hundred thirty-one billion, three hundred ten million, forty-one thousand, twenty".