Base | Representation |
---|---|
bin | 1100000111111111000000… |
… | …0100000011000001100101 |
3 | 1202012110102222210212100021 |
4 | 3001333300010003001211 |
5 | 3221410011121043133 |
6 | 44204153023315141 |
7 | 2544104213524516 |
oct | 301776004030145 |
9 | 52173388725307 |
10 | 13331311112293 |
11 | 427a8606380a9 |
12 | 15b384514bab1 |
13 | 7591a26a7cb5 |
14 | 34134b786a0d |
15 | 181ba0b0752d |
hex | c1ff0103065 |
13331311112293 has 2 divisors, whose sum is σ = 13331311112294. Its totient is φ = 13331311112292.
The previous prime is 13331311112281. The next prime is 13331311112341. The reversal of 13331311112293 is 39221111313331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7072823232484 + 6258487879809 = 2659478^2 + 2501697^2 .
It is a cyclic number.
It is not a de Polignac number, because 13331311112293 - 213 = 13331311104101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13331311112993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665655556146 + 6665655556147.
It is an arithmetic number, because the mean of its divisors is an integer number (6665655556147).
Almost surely, 213331311112293 is an apocalyptic number.
It is an amenable number.
13331311112293 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331311112293 is an equidigital number, since it uses as much as digits as its factorization.
13331311112293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8748, while the sum is 34.
The spelling of 13331311112293 in words is "thirteen trillion, three hundred thirty-one billion, three hundred eleven million, one hundred twelve thousand, two hundred ninety-three".
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