Base | Representation |
---|---|
bin | 1100000111111111000010… |
… | …1010111011001111101111 |
3 | 1202012110110200222122210122 |
4 | 3001333300222323033233 |
5 | 3221410021223212142 |
6 | 44204154025555155 |
7 | 2544104366253215 |
oct | 301776052731757 |
9 | 52173420878718 |
10 | 13331321304047 |
11 | 427a86636933a |
12 | 15b3848645abb |
13 | 7591a4835c16 |
14 | 34134cc7acb5 |
15 | 181ba196c1d2 |
hex | c1ff0abb3ef |
13331321304047 has 2 divisors, whose sum is σ = 13331321304048. Its totient is φ = 13331321304046.
The previous prime is 13331321303999. The next prime is 13331321304097. The reversal of 13331321304047 is 74040312313331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13331321304047 - 220 = 13331320255471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13331321303998 and 13331321304016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13331321304097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665660652023 + 6665660652024.
It is an arithmetic number, because the mean of its divisors is an integer number (6665660652024).
Almost surely, 213331321304047 is an apocalyptic number.
13331321304047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331321304047 is an equidigital number, since it uses as much as digits as its factorization.
13331321304047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 13331321304047 its reverse (74040312313331), we get a palindrome (87371633617378).
The spelling of 13331321304047 in words is "thirteen trillion, three hundred thirty-one billion, three hundred twenty-one million, three hundred four thousand, forty-seven".
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