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13331321304047 is a prime number
BaseRepresentation
bin1100000111111111000010…
…1010111011001111101111
31202012110110200222122210122
43001333300222323033233
53221410021223212142
644204154025555155
72544104366253215
oct301776052731757
952173420878718
1013331321304047
11427a86636933a
1215b3848645abb
137591a4835c16
1434134cc7acb5
15181ba196c1d2
hexc1ff0abb3ef

13331321304047 has 2 divisors, whose sum is σ = 13331321304048. Its totient is φ = 13331321304046.

The previous prime is 13331321303999. The next prime is 13331321304097. The reversal of 13331321304047 is 74040312313331.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13331321304047 - 220 = 13331320255471 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13331321303998 and 13331321304016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13331321304097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665660652023 + 6665660652024.

It is an arithmetic number, because the mean of its divisors is an integer number (6665660652024).

Almost surely, 213331321304047 is an apocalyptic number.

13331321304047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331321304047 is an equidigital number, since it uses as much as digits as its factorization.

13331321304047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54432, while the sum is 35.

Adding to 13331321304047 its reverse (74040312313331), we get a palindrome (87371633617378).

The spelling of 13331321304047 in words is "thirteen trillion, three hundred thirty-one billion, three hundred twenty-one million, three hundred four thousand, forty-seven".