Base | Representation |
---|---|
bin | 11000110101010100… |
… | …11100000011000101 |
3 | 1021102010221200102122 |
4 | 30122222130003011 |
5 | 204301023000222 |
6 | 10042540015325 |
7 | 651246060104 |
oct | 143252340305 |
9 | 37363850378 |
10 | 13332234437 |
11 | 5721776075 |
12 | 2700b31545 |
13 | 1346177822 |
14 | 90693003b |
15 | 5306cba42 |
hex | 31aa9c0c5 |
13332234437 has 2 divisors, whose sum is σ = 13332234438. Its totient is φ = 13332234436.
The previous prime is 13332234403. The next prime is 13332234439. The reversal of 13332234437 is 73443223331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11959828321 + 1372406116 = 109361^2 + 37046^2 .
It is a cyclic number.
It is not a de Polignac number, because 13332234437 - 26 = 13332234373 is a prime.
Together with 13332234439, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13332234397 and 13332234406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13332234439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666117218 + 6666117219.
It is an arithmetic number, because the mean of its divisors is an integer number (6666117219).
Almost surely, 213332234437 is an apocalyptic number.
It is an amenable number.
13332234437 is a deficient number, since it is larger than the sum of its proper divisors (1).
13332234437 is an equidigital number, since it uses as much as digits as its factorization.
13332234437 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 108864, while the sum is 35.
Adding to 13332234437 its reverse (73443223331), we get a palindrome (86775457768).
The spelling of 13332234437 in words is "thirteen billion, three hundred thirty-two million, two hundred thirty-four thousand, four hundred thirty-seven".
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