Base | Representation |
---|---|
bin | 11000110101011011… |
… | …10100011111111111 |
3 | 1021102012121201121011 |
4 | 30122231310133333 |
5 | 204301234333043 |
6 | 10043011020051 |
7 | 651256441645 |
oct | 143255643777 |
9 | 37365551534 |
10 | 13333121023 |
11 | 5722221192 |
12 | 270129a627 |
13 | 13463c8231 |
14 | 906ac1195 |
15 | 53080459d |
hex | 31ab747ff |
13333121023 has 2 divisors, whose sum is σ = 13333121024. Its totient is φ = 13333121022.
The previous prime is 13333120991. The next prime is 13333121071. The reversal of 13333121023 is 32012133331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13333121023 - 25 = 13333120991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13333120985 and 13333121003.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13333121083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666560511 + 6666560512.
It is an arithmetic number, because the mean of its divisors is an integer number (6666560512).
Almost surely, 213333121023 is an apocalyptic number.
13333121023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13333121023 is an equidigital number, since it uses as much as digits as its factorization.
13333121023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 13333121023 its reverse (32012133331), we get a palindrome (45345254354).
The spelling of 13333121023 in words is "thirteen billion, three hundred thirty-three million, one hundred twenty-one thousand, twenty-three".
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