13333121434000 has 40 divisors (see below), whose sum is σ = 32239487632248. Its totient is φ = 5333248572800.

The previous prime is 13333121433997. The next prime is 13333121434057. The reversal of 13333121434000 is 43412133331.

It can be written as a sum of positive squares in 4 ways, for example, as 387287160976 + 12945834273024 = 622324^2 + 3598032^2 .

It is a tau number, because it is divible by the number of its divisors (40).

It is a self number, because there is not a number n which added to its sum of digits gives 13333121434000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3333278359 + ... + 3333282358.

Almost surely, 2^{13333121434000} is an apocalyptic number.

13333121434000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13333121434000 is an abundant number, since it is smaller than the sum of its proper divisors (18906366198248).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13333121434000 is an equidigital number, since it uses as much as digits as its factorization.

13333121434000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6666560740 (or 6666560724 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 13333121434000 its reverse (43412133331), we get a palindrome (13376533567331).

The spelling of 13333121434000 in words is "thirteen trillion, three hundred thirty-three billion, one hundred twenty-one million, four hundred thirty-four thousand".