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133332311113 is a prime number
BaseRepresentation
bin111110000101100111…
…0011001110001001001
3110202011011021012002221
41330023032121301021
54141031032423423
6141130234054041
712430045642051
oct1741316316111
9422134235087
10133332311113
1151600682861
1221a1087a321
13c75b38aa61
14664bc96561
153705699e5d
hex1f0b399c49

133332311113 has 2 divisors, whose sum is σ = 133332311114. Its totient is φ = 133332311112.

The previous prime is 133332311111. The next prime is 133332311171. The reversal of 133332311113 is 311113233331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 133087795344 + 244515769 = 364812^2 + 15637^2 .

It is a cyclic number.

It is not a de Polignac number, because 133332311113 - 21 = 133332311111 is a prime.

Together with 133332311111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (133332311111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66666155556 + 66666155557.

It is an arithmetic number, because the mean of its divisors is an integer number (66666155557).

Almost surely, 2133332311113 is an apocalyptic number.

It is an amenable number.

133332311113 is a deficient number, since it is larger than the sum of its proper divisors (1).

133332311113 is an equidigital number, since it uses as much as digits as its factorization.

133332311113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1458, while the sum is 25.

Adding to 133332311113 its reverse (311113233331), we get a palindrome (444445544444).

The spelling of 133332311113 in words is "one hundred thirty-three billion, three hundred thirty-two million, three hundred eleven thousand, one hundred thirteen".