Base | Representation |
---|---|
bin | 1100001000000110100001… |
… | …1110011100111100001111 |
3 | 1202012122122210011001001022 |
4 | 3002001220132130330033 |
5 | 3221423130303100421 |
6 | 44205125311104355 |
7 | 2544205244040104 |
oct | 302015036347417 |
9 | 52178583131038 |
10 | 13333331300111 |
11 | 42806a7a13109 |
12 | 15b41098120bb |
13 | 7594350a00c4 |
14 | 34149dbb8aab |
15 | 181c6d1567ab |
hex | c206879cf0f |
13333331300111 has 2 divisors, whose sum is σ = 13333331300112. Its totient is φ = 13333331300110.
The previous prime is 13333331300039. The next prime is 13333331300117. The reversal of 13333331300111 is 11100313333331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13333331300111 - 210 = 13333331299087 is a prime.
It is a super-2 number, since 2×133333313001112 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13333331300117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6666665650055 + 6666665650056.
It is an arithmetic number, because the mean of its divisors is an integer number (6666665650056).
Almost surely, 213333331300111 is an apocalyptic number.
13333331300111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13333331300111 is an equidigital number, since it uses as much as digits as its factorization.
13333331300111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2187, while the sum is 26.
Adding to 13333331300111 its reverse (11100313333331), we get a palindrome (24433644633442).
The spelling of 13333331300111 in words is "thirteen trillion, three hundred thirty-three billion, three hundred thirty-one million, three hundred thousand, one hundred eleven".
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